This is the version 5bd1a3f008367b39f3d7b569 from 2018-10-25 11:07:28 comment: 'Maurer-Cartan form'
Lie groups ed
Table of Contents
Definition ed
- Lie group \[G\]
- A smooth manifold, with smooth multiplication \[\mu : G \times G \rightarrow G\] and inversion \[i : G \rightarrow G\].
- Left translation
- Diffeomorphism \[L_g : G \rightarrow G, L_g(a) = ga \]
- Lie algebra \[\mathfrak{g}\]
- Tangential space at the identity: \[\mathfrak{g} = T_e G\]...
Maurer-Cartan form ed
Definition ed
- Maurer-Cartan form \[\omega\]
- Left-invariant \[\mathfrak{g}\]-valued 1-form \[\omega : TG \rightarrow \mathfrak{g}\] with \[ \omega(v) = L_{g^{-1}\star} (v) \] for \[v \in T_gG\].
"moving a tangential vector from point \[g\] to \[e\] via the natural isomorphism of \[L_{g^{-1}}\]."
For matrices \[M \in GL(n)\], the Maurer-Cartan form is \[\omega = M^{-1} dM\].
Structure equations ed
- \[ d\omega + \frac{1}{2} [\omega \wedge \omega] = 0 \]
- proof
- in general \[ d\omega(X,Y) = X \omega(Y) + Y \omega(X) - \omega([X,Y]) \]
- taking \[X,Y\] left-invariant, \[\omega(Y) = \operatorname{const}\] and so \[X \omega(Y) = Y \omega(X) = 0\]
- \[[X,Y]\] is also left-invariant, so \[\omega([X,Y]) = [X,Y]_e = [X_e, Y_e] = [\omega(X), \omega(Y)] = \frac{1}{2} [\omega \wedge \omega](X,Y)\]
- since the form \[ d\omega + \frac{1}{2} [\omega \wedge \omega] \] vanishes for all left-invariant vector fields, it has to vanish in general
Categories: Mathematik, Algebra